Solution 103340

Submitted on 27 Jun 2012 by Dirk Engel

Correct

10Size

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Dirk Engel on 27 Jun 2012

It works, but it's ugly :-)

Chang Ho on 6 Aug 2012

Nice! :)

Marlies on 16 Nov 2012

Never realized that MATLAB sees a defined assignment (y = 2*x) different than no assignment (2*x => assignment to ans). If anything, I would have guessed the second would be (slightly) more effort.

Zaka on 23 Mar 2013

does this variable "ans" overrides MATLAB's default "ans"?

David Amor on 27 Apr 2013

ok, i got there in the end. but it defeats the rules - there is no "y" variable when you change the template to ans = times2(x)... how do you know what the rules are?!?