passing whole function expression as function argument

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buscuit
buscuit el 19 de Nov. de 2015
Comentada: buscuit el 24 de Nov. de 2015
hi everyone,
I am trying to create a function that has as an argument another function expression. I can manage to do this:
function [out1] = my_func(in1).
Then I can use a whole function expression as in1 like this:
[out1] = my_func( another_func() ).
So far so good.
My problem arises when the function another_function() has more than one outputs. So when another_func() is something like this:
function [out2 out3] = another_func(in2)
then [out1] = my_func( another_func() ) will only return the first of the outputs of another_func() which is out2.
Is there any way to use the expression [out1] = my_func( another_func() ) and get all outputs of another_func()?
thank you in advance for your help

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Walter Roberson
Walter Roberson el 19 de Nov. de 2015
Yes, but only in a very restricted context.
If you have an anonymous function A that effectively just calls another function B and B returns multiple outputs, then those multiple outputs will be returned from A.
For example,
my_anonymous_func = @() another_func(in)
then because another_func returns multiple outputs, they will all be returned from my_anonymous_func
I do not know if this is strictly the only sequence it will work in: it might also be possible in the form
function [varargout] = my_func(in1)
[varargout{1:nargout}] = another_func(in1);
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Walter Roberson
Walter Roberson el 23 de Nov. de 2015
The particular form
my_func(@() another_func(in1))
can use any function provided that in1 (or the other parameters) is known before the call to my_func .
If you want a function that takes two functions as inputs, then for example
function out = my_func(data, func1, func2)
out = func2(func1(data));
which could be called as
y = my_func(x, @butter, @cheby1)
The key is passing function handles
buscuit
buscuit el 24 de Nov. de 2015
Walter, thank you very much for all your feedback

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