How to arrange answers for iterations

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Arjun
Arjun el 31 de Mayo de 2014
Comentada: Arjun el 1 de Jun. de 2014
I have the following iteration running.
a=20000:5000:90000
for ct1=1:1:length(a)
b=300:20:460
for ct2=1:1:length(b)
c=150:10:300
for ct3=1:1:length(c)
d=0.5:0.1:0.8
for ct4=1:1:length(d)
e=2000:100:2300
for ct5=1:1:length(e)
x(ct1,ct2,ct3,ct4,ct5)=a(ct1)+ b(ct2)- (c(ct3))^2 + d(ct4)+ e(ct5)
end
end
end
end
end
how can I program it such that I will have all the value arranged accordingly each time the iteration runs. Example
a=20000, b=300, c=150, d=0.5, e=2000, x=-199.5
then it updates for each other iterations. tq

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the cyclist
the cyclist el 31 de Mayo de 2014
Put this line in your code, just after you assign the value to x:
sprintf('a=%d, b=%d, c=%d, d=%f, e=%d, f=%f',a(ct1),b(ct2),c(ct3),d(ct4),e(ct5),x(ct1,ct2,ct3,ct4,ct5))

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